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^3-2P^2-25P-50=0
We add all the numbers together, and all the variables
-2P^2-25P=0
a = -2; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·(-2)·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*-2}=\frac{0}{-4} =0 $$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*-2}=\frac{50}{-4} =-12+1/2 $
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